generate characters with sane compile time/memory

This commit is contained in:
2026-01-07 16:36:50 -05:00
parent 4bd9100954
commit b134bea670
7 changed files with 210 additions and 80039 deletions

View File

@@ -13,29 +13,75 @@ WITH uma_names AS (
b.id AS id_b,
b.name AS name_b,
c.id AS id_c,
c.name AS name_c,
ra.relation_type
c.name AS name_c
FROM uma_names a
JOIN uma_names b ON a.id != b.id
JOIN uma_names b ON a.id != b.id -- exclude pairwise reflexive cases
JOIN uma_names c ON a.id != c.id AND b.id != c.id
JOIN succession_relation_member ra ON a.id = ra.chara_id
JOIN succession_relation_member rb ON b.id = rb.chara_id
JOIN succession_relation_member rc ON c.id = rc.chara_id
WHERE
ra.relation_type = rb.relation_type
AND ra.relation_type = rc.relation_type
), relation_trios AS (
SELECT
ra.relation_type,
ra.chara_id AS id_a,
rb.chara_id AS id_b,
rc.chara_id AS id_c
FROM succession_relation_member ra
JOIN succession_relation_member rb ON ra.relation_type = rb.relation_type
JOIN succession_relation_member rc ON ra.relation_type = rc.relation_type
), affinity AS (
SELECT
id_a,
name_a,
id_b,
name_b,
id_c,
name_c,
SUM(relation_point) AS base_affinity
trios.*,
SUM(IFNULL(relation_point, 0)) AS base_affinity
FROM trios
JOIN succession_relation sr ON trios.relation_type = sr.relation_type
GROUP BY id_a, id_b, id_c
LEFT JOIN relation_trios rt ON trios.id_a = rt.id_a AND trios.id_b = rt.id_b AND trios.id_c = rt.id_c
LEFT JOIN succession_relation sr ON rt.relation_type = sr.relation_type
GROUP BY trios.id_a, trios.id_b, trios.id_c
UNION ALL
-- A = B = C
SELECT
n.id AS id_a,
n.name AS name_a,
n.id AS id_b,
n.name AS name_b,
n.id AS id_c,
n.name AS name_c,
0 AS base_affinity
FROM uma_names n
UNION ALL
-- A = B
SELECT
n.id AS id_a,
n.name AS name_a,
n.id AS id_a,
n.name AS id_b,
m.id AS id_c,
m.name AS name_c,
0 AS base_affinity
FROM uma_names n JOIN uma_names m ON n.id != m.id
UNION ALL
-- A = C
SELECT
n.id AS id_a,
n.name AS name_a,
m.id AS id_a,
m.name AS id_b,
n.id AS id_c,
n.name AS name_c,
0 AS base_affinity
FROM uma_names n JOIN uma_names m ON n.id != m.id
UNION ALL
-- B = C
SELECT
m.id AS id_a,
m.name AS name_a,
n.id AS id_a,
n.name AS id_b,
n.id AS id_c,
n.name AS name_c,
0 AS base_affinity
FROM uma_names n JOIN uma_names m ON n.id != m.id
)
SELECT * FROM affinity
ORDER BY id_a, id_b, id_c
ORDER BY id_a, id_b, id_c